Step 1: Brief summary of the whole system
The system is made up of a total of three hydraulic systems. (Blue, Red and Yellow) the failure of the system occurs when all three systems have failed. Each hydraulic subsystem is also made of these parts, including the distribution, the public and the computing. All three subsystems are also very instrumental to the system failure. The system’s failure only occurs when all three parts fail independently to the point that none of the hydraulic systems is functional. Each of the system parts contributes to the safety of the system, however, for the subsystem. One failing can fail of the other and such can have a failure on the entire system. Each subsystem has an independent computer that operates its system and processes. Computer 1 is the master computer; the rest of the computers 2 and 3 are back up if the first Computer or the master computer fails to operate.
Step 2: hypothesizing the failure of the subsystem.
I have to propose an instance for a failure of what can cause a catastrophic failure. There are two types of hypothesis
Both the hypothesis are valid for the failure of the aircraft. However, one of the hypothesis is weighty. I have to select one of the two beliefs, which will result in a direct failure of the system and one whose likelihood of occurring is way higher than the other. I have selected the one hypothesis which give the best understanding of the whole diagram. From the hypotheses, a clear understanding of the likelihood of the aircraft’s catastrophic failure is possibly explained.
Step 3: an in-depth analysis of the system.
To effectively analyze the system to develop the aspect of possible failure within it, it is critical for a proper understanding of the same to be first developed. The existing explanation states that, The Computing part is common for the three subsystems. It comprises three computers (Computer 1, Computer 2, and Computer 3), one of them acting as a master (controlling all the hydraulics) and the other two as backup that take control in case the master fails. The Computing part fails when the three computers fail. Every Computer is composed by one hardware element and two software elements.
The three elements are DAL C (Design Assurance Level C). A computer fails if any of these three elements fail. From this understanding a perfect probability of system failure is possible. Using hypothesis two, a failure of computer 2 and 3 which are backup Computer, begins with the first one’s failure. The first Computer has to occur for the system computer 2 and 3 to be functional. Each Hydraulic Subsystem has a Distribution Part (pipes, filter, valves, etc.), with such redundancy and robustness, this figure of reliability is 99, 9999% in 1 hour of flight. This is the most critical aspect for the examination of the failure probability for the craft.
Step 4: drawing the dependency diagram
I have to constructs a dependency diagram for all the aircraft.
Since all the three computers are all key in the continued operation of the aircrafts. The failure of one is a perfect failure of all the Computer and hence results in the entire craft’s failure. There are two pumps in each subsystem (i.e. 3A and 3B in the Red Hydraulic Subsystem). The individual pump has a MTBF (Mean Time between Failures) of 105 hours. During normal operation the A pump of each Hydraulic Subsystem is providing pressure, while the B pump is in standby in case A fails.
The failure of the whole system depends on the individual failure of the subsystems. The probability of the whole system depends on the Computer’s failure and that of computer 2 and 3. However. From the analysis of the system, if the system 1 or computer 1 fails, the whole system has two other computers to arrest the failure of the whole system by continuing with the operation of the system. One subsystem fails when any of the three parts fails.
Calculation of probabilities
The probability of the entire system fails is this given by the probability of each subsystem failure
This is; probability of either system 1 or system 2 or system three failing
Pf all system= pS1 Xps2 X pS3.
Probability of all whole system failure= pS1 Xps2 X pS3.
But the probability of S1 failing is higher
System the probability of the system 1 failure is relatively hire because it is the primary operator. The probability function of the other are resented as shown below
Probability of system failure is Ps1> Ps2 and Ps3
𝑷𝒇all systems 𝒔𝒚𝒔𝒕𝒆𝒎 = 𝑷𝒇𝒂𝟒 5−𝟗
Probability of failures
Probability of system failures
Probability all systems 4
𝒍(𝒆 𝒍𝒏(0.2 – 4)
Failure probability = 3/6
Belcastro, C. M., Klyde, D. H., Logan, M. J., Newman, R. L., & Foster, J. V. (2017). Experimental flight testing for assessing the safety of unmanned aircraft system safety-critical operations. In 17th AIAA Aviation Technology, Integration, and Operations Conference (p. 3274).
Washington, A., Clothier, R. A., & Williams, B. P. (2017). A Bayesian approach to system safety assessment and compliance assessment for Unmanned Aircraft Systems. Journal of Air Transport Management, 62, 18-33.
Washington, A., Clothier, R., Williams, B., & Silva, J. (2017). Managing uncertainty in the system safety assessment of unmanned aircraft systems. In AIAC 2017 (pp. 611-618). Engineers Australia.
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